To determine when \( f(x) \) is greater than \( g(x) \) based on the given table of values:
| x | f(x) | g(x) | |------|--------|--------| | -2 | -1 | 3 | | -1 | 3/4 | 3/4 | | 0 | 1 | 0 | | 1 | 1 1/4 | 3/4 | | 2 | 3 | 3 |
Now, let's evaluate where \( f(x) > g(x) \):
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For \( x = -2 \):
- \( f(-2) = -1 \) and \( g(-2) = 3 \): \( -1 < 3 \) (not greater)
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For \( x = -1 \):
- \( f(-1) = 3/4 \) and \( g(-1) = 3/4 \): \( 3/4 = 3/4 \) (not greater)
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For \( x = 0 \):
- \( f(0) = 1 \) and \( g(0) = 0 \): \( 1 > 0 \) (greater)
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For \( x = 1 \):
- \( f(1) = 1 1/4 \) and \( g(1) = 3/4 \): \( 1 1/4 > 3/4 \) (greater)
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For \( x = 2 \):
- \( f(2) = 3 \) and \( g(2) = 3 \): \( 3 = 3 \) (not greater)
Summary:
From the evaluations:
- \( f(x) > g(x) \) at \( x = 0 \) and \( x = 1 \).
Thus, we can conclude that \( f(x) \) is greater than \( g(x) \) specifically for the range where \( 0 \leq x < 2 \).
Final Conclusion
The correct range where \( f(x) > g(x) \) in this case is:
0 < x < 2.