Question
Electromagnet
Current Intensity
Number of Turns in the Wire
10
W
medium
X
low
10
Y
Z
medium
50
low
50
Which electromagnet will produce the strongest magnetic force?
(1 point)
electromagnet X
electromagnet Z
electromagnet W
electromagnet Y
Answers
GPT-4o mini
To determine which electromagnet will produce the strongest magnetic force, we need to consider the formula for the magnetic force produced by an electromagnet, which is generally given by the equation:
\[ F \propto I \times N \]
Where:
- \( F \) is the magnetic force,
- \( I \) is the current intensity (higher current produces a stronger magnetic field),
- \( N \) is the number of turns in the wire (more turns result in a stronger magnetic field).
Now, let's analyze each electromagnet based on the provided information:
1. **Electromagnet W**:
- Current Intensity: 10 (medium)
- Number of Turns: 10
\[
F_W \propto 10 \times 10 = 100
\]
2. **Electromagnet X**:
- Current Intensity: X (low)
- Number of Turns: 10
\[
F_X \propto \text{low} \times 10 = \text{low}
\]
3. **Electromagnet Y**:
- Current Intensity: Y (medium)
- Number of Turns: Z (medium)
\[
F_Y \propto \text{medium} \times \text{medium} = \text{medium}
\]
4. **Electromagnet Z**:
- Current Intensity: 50 (low)
- Number of Turns: 50
\[
F_Z \propto 50 \times 50 = 2500
\]
Now let’s compare the values:
- Electromagnet W: 100
- Electromagnet X: low
- Electromagnet Y: medium
- Electromagnet Z: 2500
From this comparison, Electromagnet Z will produce the strongest magnetic force.
Thus, the answer is **electromagnet Z**.
\[ F \propto I \times N \]
Where:
- \( F \) is the magnetic force,
- \( I \) is the current intensity (higher current produces a stronger magnetic field),
- \( N \) is the number of turns in the wire (more turns result in a stronger magnetic field).
Now, let's analyze each electromagnet based on the provided information:
1. **Electromagnet W**:
- Current Intensity: 10 (medium)
- Number of Turns: 10
\[
F_W \propto 10 \times 10 = 100
\]
2. **Electromagnet X**:
- Current Intensity: X (low)
- Number of Turns: 10
\[
F_X \propto \text{low} \times 10 = \text{low}
\]
3. **Electromagnet Y**:
- Current Intensity: Y (medium)
- Number of Turns: Z (medium)
\[
F_Y \propto \text{medium} \times \text{medium} = \text{medium}
\]
4. **Electromagnet Z**:
- Current Intensity: 50 (low)
- Number of Turns: 50
\[
F_Z \propto 50 \times 50 = 2500
\]
Now let’s compare the values:
- Electromagnet W: 100
- Electromagnet X: low
- Electromagnet Y: medium
- Electromagnet Z: 2500
From this comparison, Electromagnet Z will produce the strongest magnetic force.
Thus, the answer is **electromagnet Z**.