Let the three consecutive odd integers be represented as \( x \), \( x + 2 \), and \( x + 4 \).
The sum of these integers can be expressed as:
\[ x + (x + 2) + (x + 4) = 33 \]
Combining the terms gives:
\[ 3x + 6 = 33 \]
Next, we solve for \( x \) by subtracting 6 from both sides:
\[ 3x = 33 - 6 \] \[ 3x = 27 \]
Now, divide both sides by 3:
\[ x = \frac{27}{3} = 9 \]
Now that we have \( x \), we can find the three consecutive odd integers:
- First integer: \( x = 9 \)
- Second integer: \( x + 2 = 11 \)
- Third integer: \( x + 4 = 13 \)
Thus, the three consecutive odd integers are:
\[ \boxed{9, 11, 13} \]