Question

Rhombus WXYZ has vertices W(1,2), X(4,3), Y(3,0) and Z(0,-1). Find the lengths of diagonals WY and XZ.
a.)WY=2√2; XZ=4√2
b.)WY=2√4; XZ=2√2
c.)WY=2√4; XZ=4√2

Answer 1

WY = √((3-1)^2 + (0-2)^2)
= √(4+4) = √8 = 2√2
XZ = √(4^2 + 4^2)
= √32 = 4√2

Answer 2

Thanks:)