Question
Solve e2x = 50. Round to the thousandths place.
x = 0.849
x = 1.699
x = 1.956
x = 3.912
x = 0.849
x = 1.699
x = 1.956
x = 3.912
Answers
GPT-4o mini
To solve the equation \( e^{2x} = 50 \), we can take the natural logarithm of both sides.
First, take the natural logarithm:
\[
\ln(e^{2x}) = \ln(50)
\]
Using the property of logarithms, \(\ln(e^a) = a\), we can simplify the left side:
\[
2x = \ln(50)
\]
Now, we can solve for \(x\) by dividing by 2:
\[
x = \frac{\ln(50)}{2}
\]
Next, calculate \(\ln(50)\):
Using a calculator, we find:
\[
\ln(50) \approx 3.912
\]
So:
\[
x = \frac{3.912}{2} \approx 1.956
\]
Rounding to the thousandths place, we get:
\[
x \approx 1.956
\]
Thus, the correct answer is:
\(\boxed{1.956}\)
First, take the natural logarithm:
\[
\ln(e^{2x}) = \ln(50)
\]
Using the property of logarithms, \(\ln(e^a) = a\), we can simplify the left side:
\[
2x = \ln(50)
\]
Now, we can solve for \(x\) by dividing by 2:
\[
x = \frac{\ln(50)}{2}
\]
Next, calculate \(\ln(50)\):
Using a calculator, we find:
\[
\ln(50) \approx 3.912
\]
So:
\[
x = \frac{3.912}{2} \approx 1.956
\]
Rounding to the thousandths place, we get:
\[
x \approx 1.956
\]
Thus, the correct answer is:
\(\boxed{1.956}\)