Question
Solve for xx. Round to the nearest tenth, if necessary.
O
P
Q
19°
x
33
Answer
so p-Q is 33
and p has a 90 degree angle
Attempt 2 out of 2
O
P
Q
19°
x
33
Answer
so p-Q is 33
and p has a 90 degree angle
Attempt 2 out of 2
Answers
GPT-4o mini
It appears that you have a triangle where angle \( O \) is \( 19^\circ \), angle \( P \) is a right angle (\( 90^\circ \)), and side \( PQ \) (opposite angle \( O \)) has a length of \( 33 \).
To find the length of side \( x \) (which we'll assume is side \( OP \), adjacent to angle \( O \)), you can use basic trigonometric functions. Since you have an angle and need to find the length of the adjacent side, you can use the tangent function:
\[
\tan(O) = \frac{\text{opposite}}{\text{adjacent}}
\]
In this case:
\[
\tan(19^\circ) = \frac{33}{x}
\]
To solve for \( x \):
1. Rearrange the equation:
\[
x = \frac{33}{\tan(19^\circ)}
\]
2. Calculate \( \tan(19^\circ) \) (you can use a calculator):
\[
\tan(19^\circ) \approx 0.3443
\]
3. Substitute the value back into the equation:
\[
x = \frac{33}{0.3443} \approx 95.9
\]
So, the length of side \( OP \) is approximately \( 95.9 \) units when rounded to the nearest tenth.
To find the length of side \( x \) (which we'll assume is side \( OP \), adjacent to angle \( O \)), you can use basic trigonometric functions. Since you have an angle and need to find the length of the adjacent side, you can use the tangent function:
\[
\tan(O) = \frac{\text{opposite}}{\text{adjacent}}
\]
In this case:
\[
\tan(19^\circ) = \frac{33}{x}
\]
To solve for \( x \):
1. Rearrange the equation:
\[
x = \frac{33}{\tan(19^\circ)}
\]
2. Calculate \( \tan(19^\circ) \) (you can use a calculator):
\[
\tan(19^\circ) \approx 0.3443
\]
3. Substitute the value back into the equation:
\[
x = \frac{33}{0.3443} \approx 95.9
\]
So, the length of side \( OP \) is approximately \( 95.9 \) units when rounded to the nearest tenth.