To find the efficiency of energy transfer from the harbor seal to the polar bear, we can use the formula provided:
\[ \text{Efficiency} = \left( \frac{\text{Energy level transferred to next level}}{\text{Total energy input}} \right) \times 100 \]
In this case:
- Energy level transferred to the polar bear = 375 Kcal (energy that the polar bear receives from the harbor seal)
- Total energy input (energy from the harbor seal) = 2500 Kcal
Now plug in the values:
\[ \text{Efficiency} = \left( \frac{375 \text{ Kcal}}{2500 \text{ Kcal}} \right) \times 100 \]
Calculating the fraction:
\[ \frac{375}{2500} = 0.15 \]
Now multiply by 100 to get the efficiency percentage:
\[ 0.15 \times 100 = 15% \]
So, the efficiency of energy transfer between the harbor seal and the polar bear is 15%.