The problem seeks to provide another method of solving \( 28 \times 16 \) aside from the partial products method. The vertical multiplication method is a suitable alternative.
In vertical multiplication, you would write the numbers one below the other and multiply each digit separately, before adding those products together to get the final result.
One way to perform vertical multiplication for \( 28 \times 16 \) is structured as follows:
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Multiply the number in the ones place of the second number (6) by each digit of the first number (28).
- \( 6 \times 8 = 48 \) (write down 8 and carry over 4)
- \( 6 \times 2 = 12 + 4 (carry) = 16\) (place 16 to the left of the 8 giving 168)
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Multiply the number in the tens place of the second number (1) by each digit of the first number (28), remembering to shift one place to the left for the tens place multiplication.
- \( 1 \times 8 = 8 \) (write as 80 when shifting left)
- \( 1 \times 2 = 2 \) (write as 200 when shifting left)
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Now, write the added products:
- The first row is \( 168 \)
- The second row (shifted left) is \( 280 \)
- Adding \( 168 + 280 \) gives the total: \( 448 \).
From the options provided, the solution that summarizes this process correctly and effectively showcases it as vertical multiplication would be:
"Vertical multiplication shows 28 times 16 with each digit a different color. Below is a line, then 2 rows of numbers: 168, a + sign, and 280. Below is a line."
This option highlights an organized approach to vertical multiplication, leading directly to the final result.
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