Question
Liam is solving 12 × 14.
Enter a digit in each box to fill in Liam’s missing work.
Clear Check
1 2
×
1 4
+ 1 2 0
Enter a digit in each box to fill in Liam’s missing work.
Clear Check
1 2
×
1 4
+ 1 2 0
Answers
GPT-4o mini
To fill in Liam’s missing work while solving \( 12 \times 14 \), we can break it down step-by-step:
1. **Set up the multiplication**:
```
12
× 14
```
2. **Multiply the ones place**:
- 4 (from 14) multiplied by 2 (the ones place of 12):
\[
4 \times 2 = 8
\]
3. **Multiply the tens place (4 again)**:
- 4 multiplied by 1 (the tens place of 12):
\[
4 \times 1 = 4
\]
Because we are in the tens place, we write this as \( 40 \) (just put a zero).
So the first row of the addition for \( 12 \times 4 \) will be:
```
8 (from 2 × 4)
+ 40 (from 1 × 4)
-----
48 (this would actually be added separately)
```
4. **Move to the next row for the tens place**:
- Now multiply 10 (from 12, which is 1 in the tens place multiplied by 14):
```
10 (actually 1 × 14)
+ 120 (since we'll effectively be doing this, adding that 1 from moving over)
```
- 1 multiplied by 4 again in the tens adds no new work, so we concatenate as it is.
Putting it all together in the addition step:
```
8
+ 40
+ 120
-----
168 (final result after all additions)
```
So, filling in Liam's table:
```
1 2
× 1 4
-----------------
8
+ 4 0
+ 1 2 0
-----------------
1 6 8 (Final answer)
```
Thus, the digits to fill in would be:
1st Box: **8**
2nd Box: **4**
3rd Box: **0**
4th Box: **2**
5th Box: **1** (Since we have 12 in tens)
Bottom Box: **6** (Final result at the bottom)
So the answer to fill in the boxes appropriately is:
```
8
+ 40
+ 120
```
Final answer is that last row would result in **1 6 8** after all proper additions done correctly.
1. **Set up the multiplication**:
```
12
× 14
```
2. **Multiply the ones place**:
- 4 (from 14) multiplied by 2 (the ones place of 12):
\[
4 \times 2 = 8
\]
3. **Multiply the tens place (4 again)**:
- 4 multiplied by 1 (the tens place of 12):
\[
4 \times 1 = 4
\]
Because we are in the tens place, we write this as \( 40 \) (just put a zero).
So the first row of the addition for \( 12 \times 4 \) will be:
```
8 (from 2 × 4)
+ 40 (from 1 × 4)
-----
48 (this would actually be added separately)
```
4. **Move to the next row for the tens place**:
- Now multiply 10 (from 12, which is 1 in the tens place multiplied by 14):
```
10 (actually 1 × 14)
+ 120 (since we'll effectively be doing this, adding that 1 from moving over)
```
- 1 multiplied by 4 again in the tens adds no new work, so we concatenate as it is.
Putting it all together in the addition step:
```
8
+ 40
+ 120
-----
168 (final result after all additions)
```
So, filling in Liam's table:
```
1 2
× 1 4
-----------------
8
+ 4 0
+ 1 2 0
-----------------
1 6 8 (Final answer)
```
Thus, the digits to fill in would be:
1st Box: **8**
2nd Box: **4**
3rd Box: **0**
4th Box: **2**
5th Box: **1** (Since we have 12 in tens)
Bottom Box: **6** (Final result at the bottom)
So the answer to fill in the boxes appropriately is:
```
8
+ 40
+ 120
```
Final answer is that last row would result in **1 6 8** after all proper additions done correctly.