Let's analyze each of the four mathematical situations one by one.
-
Jose has 4 packs of gum and 10 pieces of gum in each pack:
- \( 4 \text{ packs} \times 10 \text{ pieces per pack} = 40 \text{ pieces of gum} \)
- So, Jose has 40 pieces of gum. (Option a)
-
Jose owes each of 4 friends $10:
- Total debt = \( 4 \text{ friends} \times 10 \text{ dollars each} = 40 \text{ dollars} \)
- So, Jose owes a total of $40.00. (This does not fit any of the options explicitly but corresponds with the idea of adding up to 40.)
-
Jose spent $4 for each of 10 baseball cards for his collection:
- Total spent = \( 10 \text{ cards} \times 4 \text{ dollars each} = 40 \text{ dollars} \)
- So, Jose spent a total of $40.00. (Again, reconciliation with provided choices is implicit as the calculation indicates a total of $40.)
-
Jose drank 4 ounces of juice on each of the previous 10 days:
- Total juice consumed = \( 4 \text{ ounces/day} \times 10 \text{ days} = 40 \text{ ounces} \)
- So, Jose had 40 more ounces of juice ten days ago. (This does not fit the options exactly as proposed for the calculation but is taken as per given conditions.)
Thus, the answers are:
- Jose has 40 pieces of gum. (Option a)
- Jose owes a total of $40.00.
- Jose spent a total of $40.00.
- Jose had 40 more ounces of juice ten days ago.
To summarize:
- Jose has 40 pieces of gum.
- Jose owes a total of $40.00.
- Jose spent a total of $40.00.
- Jose had 40 more ounces of juice ten days ago.