Asked by Ariel
A line has a slope m=1/3 and it passes through the point (3, 4). Find the equation for the line in slope-intercept form.
a.)y = 1/3x + 3
b.)y - 4 = 1/3(x - 3)
c.)y - 3 = 1/3(x - 4)
a.)y = 1/3x + 3
b.)y - 4 = 1/3(x - 3)
c.)y - 3 = 1/3(x - 4)
Answers
Answered by
Ariel
I figured out the answer by using the slope intercept formula:
y-y1=m(x-x1)
y - 4 = 1/3(x - 3)
y-y1=m(x-x1)
y - 4 = 1/3(x - 3)
Answered by
Reiny
the slope intercept form has the appearance of
y = mx+b
so you will have to continue with your correct starting equation
y - 4 = 1/3(x - 3)
y - 4 = (1/3)x - 1
y = (1/3)x - 1 + 4
y = (1/3)x + 3 , which is choice a)
y = mx+b
so you will have to continue with your correct starting equation
y - 4 = 1/3(x - 3)
y - 4 = (1/3)x - 1
y = (1/3)x - 1 + 4
y = (1/3)x + 3 , which is choice a)
Answered by
Ariel
Thanks:)
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