Asked by bb
I am terrible at word problems. How do I work this?
A large park is to be built in the shape of a rectangle. The length is to be 5 m shorter than three times the width. The perimeter of the park is to be 750 m. What will be the length and
width of the park?
A large park is to be built in the shape of a rectangle. The length is to be 5 m shorter than three times the width. The perimeter of the park is to be 750 m. What will be the length and
width of the park?
Answers
Answered by
Reiny
The main idea is to "translate" the English into math
let the width be x
"The length is to be 5 m shorter than three times the width."
length = 3x-5
so now we know the width is x
and the length is 3x-5
"The length is to be 5 m shorter than three times the width."
Isn't perimeter the sum of all the sides ? So ...
x + x + 3x-5 + 3x-5 = 750
now you have an easy equation to solve, let me know what you got.
let the width be x
"The length is to be 5 m shorter than three times the width."
length = 3x-5
so now we know the width is x
and the length is 3x-5
"The length is to be 5 m shorter than three times the width."
Isn't perimeter the sum of all the sides ? So ...
x + x + 3x-5 + 3x-5 = 750
now you have an easy equation to solve, let me know what you got.
Answered by
bb
8x+(-10)=750
8x=760
x=95
y=95(3)=285
w=95
L=285
8x=760
x=95
y=95(3)=285
w=95
L=285
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