Question
Martha opened a savings account 8 years ago. The account earns 6% interest, compounded continuously. If the current balance is $500.00, how much did she deposit initially?
Use the formula A=Pert, where A is the balance (final amount), P is the principal (starting amount), e is the base of natural logarithms (≈2.71828), r is the interest rate expressed as a decimal, and t is the time in years.
Round your answer to the nearest cent.
Use the formula A=Pert, where A is the balance (final amount), P is the principal (starting amount), e is the base of natural logarithms (≈2.71828), r is the interest rate expressed as a decimal, and t is the time in years.
Round your answer to the nearest cent.
Answers
Answered by
GPT-4o mini
To find the initial deposit (P) that Martha made, we can rearrange the formula for continuous compounding interest \( A = Pe^{rt} \).
Given:
- \( A = 500 \)
- \( r = 0.06 \) (since 6% expressed as a decimal is 0.06)
- \( t = 8 \)
We can substitute these values into the formula and solve for \( P \):
\[
500 = Pe^{0.06 \times 8}
\]
First, calculate \( e^{0.48} \) (since \( 0.06 \times 8 = 0.48 \)):
\[
e^{0.48} \approx 1.616
\]
Now substitute this value back into the equation:
\[
500 = P \times 1.616
\]
Now, solve for \( P \):
\[
P = \frac{500}{1.616} \approx 309.55
\]
Thus, the initial deposit Martha made is approximately **$309.55**.
Given:
- \( A = 500 \)
- \( r = 0.06 \) (since 6% expressed as a decimal is 0.06)
- \( t = 8 \)
We can substitute these values into the formula and solve for \( P \):
\[
500 = Pe^{0.06 \times 8}
\]
First, calculate \( e^{0.48} \) (since \( 0.06 \times 8 = 0.48 \)):
\[
e^{0.48} \approx 1.616
\]
Now substitute this value back into the equation:
\[
500 = P \times 1.616
\]
Now, solve for \( P \):
\[
P = \frac{500}{1.616} \approx 309.55
\]
Thus, the initial deposit Martha made is approximately **$309.55**.
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