Question
There are three 20.0 Ohm resistors connected in series across a 120 V generator. What is the total resistance of the circuit?
90 Ω
120 Ω
30 Ω
60 Ω
90 Ω
120 Ω
30 Ω
60 Ω
Answers
GPT-4o mini
To find the total resistance of resistors connected in series, you simply add their resistances together.
In this case, there are three 20.0 Ohm resistors.
Total resistance \( R_{\text{total}} \) is given by:
\[
R_{\text{total}} = R_1 + R_2 + R_3
\]
Substituting the values:
\[
R_{\text{total}} = 20.0 \, \Omega + 20.0 \, \Omega + 20.0 \, \Omega = 60.0 \, \Omega
\]
Thus, the total resistance of the circuit is **60 Ω**.
In this case, there are three 20.0 Ohm resistors.
Total resistance \( R_{\text{total}} \) is given by:
\[
R_{\text{total}} = R_1 + R_2 + R_3
\]
Substituting the values:
\[
R_{\text{total}} = 20.0 \, \Omega + 20.0 \, \Omega + 20.0 \, \Omega = 60.0 \, \Omega
\]
Thus, the total resistance of the circuit is **60 Ω**.