To determine which function has a y-intercept, we need to evaluate both functions at \( x = 0 \) and see if they yield a valid output.
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For the first function, \( f(x) = \sqrt{x - 2} \):
- When \( x = 0 \): \[ f(0) = \sqrt{0 - 2} = \sqrt{-2} \] This is not a real number, so there is no y-intercept for \( f(x) \).
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For the second function, \( g(x) = \sqrt{2 - x} \):
- When \( x = 0 \): \[ g(0) = \sqrt{2 - 0} = \sqrt{2} \] This is a valid real number, so there is a y-intercept at \( y = \sqrt{2} \).
Therefore, the answer is:
Option 2: g(x)