To solve the equation \( x^2 + 8x - 15 = 5 \) by inspection, first, we can simplify the equation by moving all terms to one side:
\[ x^2 + 8x - 15 - 5 = 0 \]
This simplifies to:
\[ x^2 + 8x - 20 = 0 \]
Next, we can factor the quadratic equation or look for integer solutions that would satisfy the equation.
We need two numbers that multiply to \(-20\) and add to \(8\). The pairs of factors of \(-20\) are:
- \(1\) and \(-20\) (adds to \(-19\))
- \(-1\) and \(20\) (adds to \(19\))
- \(2\) and \(-10\) (adds to \(-8\))
- \(-2\) and \(10\) (adds to \(8\))
- \(4\) and \(-5\) (adds to \(-1\))
- \(-4\) and \(5\) (adds to \(1\))
The pair that works is \(-2\) and \(10\).
So, the solutions to the equation \(x^2 + 8x - 20 = 0\) are:
- \(x = 10\)
- \(x = -2\)
Thus, the two solutions from the provided options are:
- \(x = 10\)
- \(x = -2\)