Asked by d
Evaluate log(10^4⋅8)
.(1 point)
Responses
log(10^4⋅8)=log(4+8)
logarithm left parenthesis 10 superscript 4 baseline times 8 right parenthesis equals logarithm left parenthesis 4 plus 8 right parenthesis
log(10^4⋅8)=4+log8
logarithm left parenthesis 10 superscript 4 baseline times 8 right parenthesis equals 4 plus logarithm 8
log(10^4⋅8)=log(4⋅8)
logarithm left parenthesis 10 superscript 4 baseline times 8 right parenthesis equals logarithm left parenthesis 4 times 8 right parenthesis
log(10^4⋅8)=log4+8
.(1 point)
Responses
log(10^4⋅8)=log(4+8)
logarithm left parenthesis 10 superscript 4 baseline times 8 right parenthesis equals logarithm left parenthesis 4 plus 8 right parenthesis
log(10^4⋅8)=4+log8
logarithm left parenthesis 10 superscript 4 baseline times 8 right parenthesis equals 4 plus logarithm 8
log(10^4⋅8)=log(4⋅8)
logarithm left parenthesis 10 superscript 4 baseline times 8 right parenthesis equals logarithm left parenthesis 4 times 8 right parenthesis
log(10^4⋅8)=log4+8
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To evaluate \( \log(10^4 \cdot 8) \), we can use the properties of logarithms.
1. **Product Rule:** The logarithm of a product is the sum of the logarithms:
\[
\log(a \cdot b) = \log a + \log b
\]
Using this property, we can rewrite \( \log(10^4 \cdot 8) \) as follows:
\[
\log(10^4 \cdot 8) = \log(10^4) + \log(8)
\]
2. **Power Rule:** The logarithm of a power is the exponent times the logarithm of the base:
\[
\log(a^b) = b \cdot \log(a)
\]
Thus, we can simplify \( \log(10^4) \):
\[
\log(10^4) = 4 \cdot \log(10) = 4
\]
3. **Putting it all together:**
Now substitute back:
\[
\log(10^4 \cdot 8) = \log(10^4) + \log(8) = 4 + \log(8)
\]
So, the final evaluation is:
\[
\log(10^4 \cdot 8) = 4 + \log(8)
\]
From the responses provided, the correct one is:
\[
\log(10^4 \cdot 8) = 4 + \log 8
\]
1. **Product Rule:** The logarithm of a product is the sum of the logarithms:
\[
\log(a \cdot b) = \log a + \log b
\]
Using this property, we can rewrite \( \log(10^4 \cdot 8) \) as follows:
\[
\log(10^4 \cdot 8) = \log(10^4) + \log(8)
\]
2. **Power Rule:** The logarithm of a power is the exponent times the logarithm of the base:
\[
\log(a^b) = b \cdot \log(a)
\]
Thus, we can simplify \( \log(10^4) \):
\[
\log(10^4) = 4 \cdot \log(10) = 4
\]
3. **Putting it all together:**
Now substitute back:
\[
\log(10^4 \cdot 8) = \log(10^4) + \log(8) = 4 + \log(8)
\]
So, the final evaluation is:
\[
\log(10^4 \cdot 8) = 4 + \log(8)
\]
From the responses provided, the correct one is:
\[
\log(10^4 \cdot 8) = 4 + \log 8
\]
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.