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What is the ordered pair of the endpoint in the standard form of a square root function y=5x−4−−−−√−1?(1 point) Responses (4,1)...Asked by hi
What is the ordered pair of the endpoint in the standard form of a square root function y=5√x−4−−−−−−1 ?(1 point)
Responses
(4,−1)
left parenthesis h comma k right parenthesis
(−4,1)
left parenthesis negative h comma negative k right parenthesis
(4,1)
left parenthesis h comma negative k right parenthesis
(−4,−1)
Responses
(4,−1)
left parenthesis h comma k right parenthesis
(−4,1)
left parenthesis negative h comma negative k right parenthesis
(4,1)
left parenthesis h comma negative k right parenthesis
(−4,−1)
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To identify the ordered pair of the endpoint for the square root function \( y = 5\sqrt{x-4} - 1 \), we can rewrite it in the form:
\[ y = a\sqrt{x-h} + k \]
where \( (h, k) \) is the vertex (or the endpoint for a square root function).
From the given function:
- The term inside the square root, \( x - 4 \), indicates that \( h = 4 \).
- The \( -1 \) outside the square root indicates that \( k = -1 \).
Thus, the vertex or endpoint is at the point \( (h, k) = (4, -1) \).
Therefore, the correct ordered pair that indicates the endpoint in standard form is:
**(4, -1)**.
\[ y = a\sqrt{x-h} + k \]
where \( (h, k) \) is the vertex (or the endpoint for a square root function).
From the given function:
- The term inside the square root, \( x - 4 \), indicates that \( h = 4 \).
- The \( -1 \) outside the square root indicates that \( k = -1 \).
Thus, the vertex or endpoint is at the point \( (h, k) = (4, -1) \).
Therefore, the correct ordered pair that indicates the endpoint in standard form is:
**(4, -1)**.
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