To find the y-values of the function \( y = 5(1/4)^x \) for the given x-values, we will substitute each x-value into the equation:
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For \( x = -2 \): \[ y = 5\left(\frac{1}{4}\right)^{-2} = 5 \times 4^2 = 5 \times 16 = 80 \]
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For \( x = -1 \): \[ y = 5\left(\frac{1}{4}\right)^{-1} = 5 \times 4^1 = 5 \times 4 = 20 \]
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For \( x = 0 \): \[ y = 5\left(\frac{1}{4}\right)^{0} = 5 \times 1 = 5 \]
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For \( x = 1 \): \[ y = 5\left(\frac{1}{4}\right)^{1} = 5 \times \frac{1}{4} = 5 \times 0.25 = 1.25 \]
Putting the ordered pairs together, we have:
- For \( x = -2 \): \( (−2, 80) \)
- For \( x = -1 \): \( (−1, 20) \)
- For \( x = 0 \): \( (0, 5) \)
- For \( x = 1 \): \( (1, 1.25) \)
Thus, the correct set of ordered pairs is:
(−2, 80), (−1, 20), (0, 5), and (1, 1.25).