Question
Network Communication and Organization Unit Test 13 of 2013 of 20 Items Question There are currently 254 devices connected to a hospital's network. An additional 30,000 to 65,000 devices will be added to the hospital's network during the next five years, but no more than 65,000 devices. What is the most appropriate IP address class for the hospital to accommodate its network growth?(1 point) Responses class A class A class B class B class F class F class C class C Skip to navigation page 1 of 1
Answers
GPT-4o mini
To determine the most appropriate IP address class for the hospital to accommodate its network growth, we can analyze the number of devices.
Currently, there are 254 devices connected. An additional 30,000 to 65,000 devices will be added, which means the total number of devices could range from:
- **Current devices**: 254
- **Additional devices (minimum)**: 30,000
- **Total devices (minimum)**: 254 + 30,000 = 30,254
- **Additional devices (maximum)**: 65,000
- **Total devices (maximum)**: 254 + 65,000 = 65,254
The total number of devices could therefore be as high as 65,254.
Now, let's look at the IP address classes:
- **Class A**: Supports 16 million hosts (2^24 - 2, since one address is for the network and one for the broadcast).
- **Class B**: Supports 65,534 hosts (2^16 - 2).
- **Class C**: Supports 254 hosts (2^8 - 2).
- **Class F**: Not a standard IP class used for hosts.
Since the maximum requirement is 65,254 devices, Class B would be suitable as it allows for up to 65,534 hosts, which can accommodate the hospital's current and future device needs.
Thus, the most appropriate IP address class for the hospital to accommodate its network growth is **Class B**.
Currently, there are 254 devices connected. An additional 30,000 to 65,000 devices will be added, which means the total number of devices could range from:
- **Current devices**: 254
- **Additional devices (minimum)**: 30,000
- **Total devices (minimum)**: 254 + 30,000 = 30,254
- **Additional devices (maximum)**: 65,000
- **Total devices (maximum)**: 254 + 65,000 = 65,254
The total number of devices could therefore be as high as 65,254.
Now, let's look at the IP address classes:
- **Class A**: Supports 16 million hosts (2^24 - 2, since one address is for the network and one for the broadcast).
- **Class B**: Supports 65,534 hosts (2^16 - 2).
- **Class C**: Supports 254 hosts (2^8 - 2).
- **Class F**: Not a standard IP class used for hosts.
Since the maximum requirement is 65,254 devices, Class B would be suitable as it allows for up to 65,534 hosts, which can accommodate the hospital's current and future device needs.
Thus, the most appropriate IP address class for the hospital to accommodate its network growth is **Class B**.