To find the actual distance between the two exhibits based on the scale of the drawing, we first need to determine the scale used in the drawing.
We know the two water fountains are 10 inches apart on the drawing and represent an actual distance of 400 feet.
To find the scale, we set up the relationship:
\[ \text{Scale} = \frac{\text{Actual distance}}{\text{Drawing distance}} = \frac{400 \text{ feet}}{10 \text{ inches}} \]
Now, converting 400 feet to inches, since there are 12 inches in a foot:
\[ 400 \text{ feet} = 400 \times 12 = 4800 \text{ inches} \]
Now we can find the scale:
\[ \text{Scale} = \frac{4800 \text{ inches}}{10 \text{ inches}} = 480 \text{ inches (actual) per inch (drawing)} \]
Now that we have the scale, we will use it to find the actual distance between the two exhibits, which are 3.125 inches apart on the drawing.
Using the scale:
\[ \text{Actual distance} = \text{Drawing distance} \times \text{Scale} = 3.125 \text{ inches} \times 480 \text{ inches} \]
Calculating this gives us:
\[ \text{Actual distance} = 3.125 \times 480 = 1500 \text{ inches} \]
Now converting this back to feet:
\[ 1500 \text{ inches} \div 12 \text{ inches/foot} = 125 \text{ feet} \]
Thus, the actual distance between the two exhibits is 125 feet.