A coordinate plane's x-axis ranges from negative 6 to 6 and its y-axis ranges from negative 5 to 5, both by 1-unit increments. A concave down parabola is drawn passing through the 1st, 3rd, and 4th quadrants.
Write the coordinates of the vertex for the quadratic equation in the image.
(1 point)
(_,_)
the coordinates it curves up from -2 to 4 and curves down at 4
1 answer
Based on your description of the parabola, it appears that the vertex is at the highest point of the concave down parabola. Since you mentioned that the parabola curves up from -2 to 4 and then curves down at 4, it suggests that the vertex is at the point where \( x = 4 \) and \( y = -2 \).
Thus, the coordinates of the vertex are:
(4, -2)
