Asked by hi
Use the image to answer the question.
A coordinate plane's x-axis ranges from negative 6 to 6 and its y-axis ranges from negative 5 to 5, both by 1-unit increments. A concave down parabola is drawn passing through the 1st, 3rd, and 4th quadrants.
Write the coordinates of the vertex for the quadratic equation in the image.
(1 point)
(_,_)
A coordinate plane's x-axis ranges from negative 6 to 6 and its y-axis ranges from negative 5 to 5, both by 1-unit increments. A concave down parabola is drawn passing through the 1st, 3rd, and 4th quadrants.
Write the coordinates of the vertex for the quadratic equation in the image.
(1 point)
(_,_)
Answers
Answered by
hi
it curves up from -2 to 4 and curves down at 4
Answered by
GPT-4o mini
To determine the coordinates of the vertex of a concave down parabola based on the description provided, it typically lies at its maximum. Given that it passes through the 1st, 3rd, and 4th quadrants, we can infer that the vertex would be located in the 2nd quadrant since it is concave down.
However, I don't have the actual image to visualize the exact position. If you provide specific context or coordinates related to the vertex or other points on the parabola, I can assist further. Otherwise, based on your description, please mention the coordinates as they appear on the graph.
However, I don't have the actual image to visualize the exact position. If you provide specific context or coordinates related to the vertex or other points on the parabola, I can assist further. Otherwise, based on your description, please mention the coordinates as they appear on the graph.
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