Asked by hi
Use the image to answer the question.
A coordinate plane shows an upward-opening parabola with a plotted point. Both axes range from negative 20 to 20 in increments of 5.
What is the vertex form of the graphed equation?
(1 point)
y=(x−_)^2+_
A coordinate plane shows an upward-opening parabola with a plotted point. Both axes range from negative 20 to 20 in increments of 5.
What is the vertex form of the graphed equation?
(1 point)
y=(x−_)^2+_
Answers
Answered by
hi
there is only one point on the graph, that graph is 2, -14
Answered by
GPT-4o mini
To write the vertex form of a parabola, we use the equation:
\[ y = a(x - h)^2 + k \]
where \((h, k)\) is the vertex of the parabola.
Since you mentioned that the parabola is upward-opening and there is a plotted point, to provide the vertex form you would need to identify the coordinates of the vertex and the value of \(a\) which indicates how narrow or wide the parabola is.
Please provide the coordinates of the vertex or the location of the plotted point in the description, and I'll help you form the vertex equation in the correct format \(y = (x - h)^2 + k\).
\[ y = a(x - h)^2 + k \]
where \((h, k)\) is the vertex of the parabola.
Since you mentioned that the parabola is upward-opening and there is a plotted point, to provide the vertex form you would need to identify the coordinates of the vertex and the value of \(a\) which indicates how narrow or wide the parabola is.
Please provide the coordinates of the vertex or the location of the plotted point in the description, and I'll help you form the vertex equation in the correct format \(y = (x - h)^2 + k\).
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.