Asked by adaleta
Guided Practice
Find the percent error of the measurement.
0.2 cm
A.
25%
B.
50%
C.
400%
Find the percent error of the measurement.
0.2 cm
A.
25%
B.
50%
C.
400%
Answers
Answered by
GPT-4o mini
To find the percent error of a measurement, you typically need to know both the measured value and the true or accepted value. The formula for percent error is:
\[
\text{Percent Error} = \left( \frac{|\text{True Value} - \text{Measured Value}|}{|\text{True Value}|} \right) \times 100\%
\]
In this case, you only provided the measurement of 0.2 cm, but you need the true value to calculate the percent error. If we had a true value (let's say 1 cm for the sake of an example), we would calculate it as follows:
1. Assume the true value is 1 cm (for example).
2. Measured value = 0.2 cm.
3. Calculate the error:
\[
\text{Error} = |\text{True Value} - \text{Measured Value}| = |1 - 0.2| = 0.8 \text{ cm}
\]
4. Calculate the percent error:
\[
\text{Percent Error} = \left( \frac{0.8}{1} \right) \times 100\% = 80\%
\]
Without knowing the true value, we can't definitively say which of the options A, B, or C is correct. If you provide a true value, I can help you find the accurate percent error.
If you have values for the true measurement, please share them for a clearer calculation.
\[
\text{Percent Error} = \left( \frac{|\text{True Value} - \text{Measured Value}|}{|\text{True Value}|} \right) \times 100\%
\]
In this case, you only provided the measurement of 0.2 cm, but you need the true value to calculate the percent error. If we had a true value (let's say 1 cm for the sake of an example), we would calculate it as follows:
1. Assume the true value is 1 cm (for example).
2. Measured value = 0.2 cm.
3. Calculate the error:
\[
\text{Error} = |\text{True Value} - \text{Measured Value}| = |1 - 0.2| = 0.8 \text{ cm}
\]
4. Calculate the percent error:
\[
\text{Percent Error} = \left( \frac{0.8}{1} \right) \times 100\% = 80\%
\]
Without knowing the true value, we can't definitively say which of the options A, B, or C is correct. If you provide a true value, I can help you find the accurate percent error.
If you have values for the true measurement, please share them for a clearer calculation.
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