Question
10.
Find the minimum and maximum possible areas for a rectangle measuring 4.15 cm by 7.34 cm. Round to the nearest hundredth.
Find the minimum and maximum possible areas for a rectangle measuring 4.15 cm by 7.34 cm. Round to the nearest hundredth.
Answers
GPT-4o mini
To find the minimum and maximum possible areas for a rectangle measuring 4.15 cm by 7.34 cm, we first calculate the area as follows:
\[
\text{Area} = \text{length} \times \text{width}
\]
Substituting the given values:
\[
\text{Area} = 4.15 \, \text{cm} \times 7.34 \, \text{cm}
\]
Calculating the product:
\[
\text{Area} = 30.541 \, \text{cm}^2
\]
Now, we round this result to the nearest hundredth:
\[
\text{Area} \approx 30.54 \, \text{cm}^2
\]
Since the question does not specify any variations in the dimensions of the rectangle (for example, if they could change or have a degree of uncertainty), we will assume that the measurements are precise. Therefore, there is only one area calculation.
Thus, since there is no variation provided, the minimum and maximum possible areas of the rectangle are both the same.
**Minimum Area:** 30.54 cm²
**Maximum Area:** 30.54 cm²
So, the final answer is:
- Minimum area: 30.54 cm²
- Maximum area: 30.54 cm²
\[
\text{Area} = \text{length} \times \text{width}
\]
Substituting the given values:
\[
\text{Area} = 4.15 \, \text{cm} \times 7.34 \, \text{cm}
\]
Calculating the product:
\[
\text{Area} = 30.541 \, \text{cm}^2
\]
Now, we round this result to the nearest hundredth:
\[
\text{Area} \approx 30.54 \, \text{cm}^2
\]
Since the question does not specify any variations in the dimensions of the rectangle (for example, if they could change or have a degree of uncertainty), we will assume that the measurements are precise. Therefore, there is only one area calculation.
Thus, since there is no variation provided, the minimum and maximum possible areas of the rectangle are both the same.
**Minimum Area:** 30.54 cm²
**Maximum Area:** 30.54 cm²
So, the final answer is:
- Minimum area: 30.54 cm²
- Maximum area: 30.54 cm²