To solve the system of equations:
- \( 5x - 4y = -44 \) (Equation 1)
- \( -x + 3y = 22 \) (Equation 2)
Let's use the substitution or elimination method to solve this system.
Step 1: Solve one equation for one variable
From Equation 2, solve for \( x \):
\[ -x + 3y = 22 \]
\[ -x = 22 - 3y \]
\[ x = 3y - 22 \quad \text{(Equation 3)} \]
Step 2: Substitute Equation 3 into Equation 1
Substitute (Equation 3) into Equation 1:
\[ 5(3y - 22) - 4y = -44 \]
Distribute the 5:
\[ 15y - 110 - 4y = -44 \]
Combine like terms:
\[ 11y - 110 = -44 \]
Add 110 to both sides:
\[ 11y = 110 - 44 \]
\[ 11y = 66 \]
Divide by 11:
\[ y = 6 \]
Step 3: Substitute \( y \) back to find \( x \)
Now use the value of \( y \) in Equation 3:
\[ x = 3(6) - 22 \]
\[ x = 18 - 22 \]
\[ x = -4 \]
Step 4: Write the solution
The solution to the system of equations is:
\[ (x, y) = (-4, 6) \]
Final Answer
\((-4, 6)\)