Question

A)
Hydrogen selenide (H,Se) reacts with water according to the following equation.
HaSe + H20 → SeHT + H30+
Identify the acid, base, conjugate acid, and conjugate base in this reaction
(2 points)

Acid
Base
Conjugate acid
Conjugate base
H30+
H,Se

Answer 1

In the reaction:

\[ \text{H}_2\text{Se} + \text{H}_2\text{O} \rightarrow \text{H}_3\text{O}^+ + \text{SeH}^- \]

we can identify the following:

- **Acid**: \( \text{H}_2\text{Se} \) (it donates a proton)
- **Base**: \( \text{H}_2\text{O} \) (it accepts a proton)
- **Conjugate acid**: \( \text{H}_3\text{O}^+ \) (the species formed after \( \text{H}_2\text{O} \) accepts a proton)
- **Conjugate base**: \( \text{SeH}^- \) (the species formed after \( \text{H}_2\text{Se} \) donates a proton)

Thus, the identified species are:

- Acid: \( \text{H}_2\text{Se} \)
- Base: \( \text{H}_2\text{O} \)
- Conjugate Acid: \( \text{H}_3\text{O}^+ \)
- Conjugate Base: \( \text{SeH}^- \) (though you mentioned \( \text{SeH}^- \) in the question, it appears you might have meant \( SeH^- \)).