Asked by sarah
A basketball player can jump 2.16 m off the hardwood floor. With what upward velocity did he leave the floor? (use 9.8 m/s/s)
Answers
Answered by
Ariel
Try using the velocity formula:(V=velocity, d=distance, and t=time)
V=d/t
V=d/t
Answered by
Ariel
9.8(2.16/s)=
Answered by
drwls
Ariel's answers won't be much help.
Use the fact that initial kientic energy in converted to potential energy (raising of the center of mass, by H = 2.16 m).
M g H = (1/2) M V^2
The M's cancel.
V = sqrt(2 g H) = 6.5 m/s
Use the fact that initial kientic energy in converted to potential energy (raising of the center of mass, by H = 2.16 m).
M g H = (1/2) M V^2
The M's cancel.
V = sqrt(2 g H) = 6.5 m/s
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