A basketball player can jump 2.16 m off the hardwood floor. With what upward velocity did he leave the floor? (use 9.8 m/s/s)

3 answers

Try using the velocity formula:(V=velocity, d=distance, and t=time)
V=d/t
9.8(2.16/s)=
Ariel's answers won't be much help.

Use the fact that initial kientic energy in converted to potential energy (raising of the center of mass, by H = 2.16 m).

M g H = (1/2) M V^2
The M's cancel.

V = sqrt(2 g H) = 6.5 m/s