Asked by Angela
Calculate the OH- of each aqueous solution
aspirin, 5.9×10−4 M
milk of magnesia, 1.5×10−9 M
aspirin, 5.9×10−4 M
milk of magnesia, 1.5×10−9 M
Answers
Answered by
DrBob222
Call aspirin, HA.
HA ==> H^+ + A^-
Ka = (H^+)(A^-)/(HA)
Set up an ICE chart, substitute into the Ka expression and solve for (H^+), then convert to OH^-.
Mg(OH)2 ==> Mg^+2 + 2OH^-
1.5 x 10^-9 M is less than the solubility of Mg(OH)2; therefore, this should be the (Mg^+2). Twice that will be the concn of OH^-.
HA ==> H^+ + A^-
Ka = (H^+)(A^-)/(HA)
Set up an ICE chart, substitute into the Ka expression and solve for (H^+), then convert to OH^-.
Mg(OH)2 ==> Mg^+2 + 2OH^-
1.5 x 10^-9 M is less than the solubility of Mg(OH)2; therefore, this should be the (Mg^+2). Twice that will be the concn of OH^-.
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