Let's define the variables for the problem:
- Let \( T \) be the number of punches on the tea card after \( t \) weeks.
- Let \( C \) be the number of punches on the coffee card after \( t \) weeks.
Initially, Philip has:
- \( T = 7 \) (initial punches on tea card)
- \( C = 11 \) (initial punches on coffee card)
The rate of earning punches is as follows:
- Philip earns 2 punches per week on the tea card: \( T = 7 + 2t \)
- Philip earns 1 punch per week on the coffee card: \( C = 11 + t \)
Now, we want to find when the number of punches on both cards will be the same, so we set up the equation:
\[ 7 + 2t = 11 + t \]
Now, we will solve for \( t \):
- Subtract \( t \) from both sides:
\[ 7 + 2t - t = 11 \]
- Combine like terms:
\[ 7 + t = 11 \]
- Subtract 7 from both sides:
\[ t = 11 - 7 \]
- Thus,
\[ t = 4 \]
Now, substituting \( t = 4 \) back into the equations for \( T \) and \( C \) to find the number of punches on each card:
For the tea card:
\[ T = 7 + 2(4) = 7 + 8 = 15 \]
For the coffee card:
\[ C = 11 + 4 = 15 \]
So, the final result is:
Philip will have 15 punches on each card in 4 weeks.
To summarize:
Philip will have 15 punches on each card in 4 weeks.