There are many ways you could solve this equation. We need to get v alone on one side, and a constant number alone on the other side. Since v is inside the parentheses on the left, we can use the distributive property to rewrite the equation without parentheses. Go for it. Distribute the

Question

5
1
​
to 15v−10. You can think of this as (15v−10) is being multiplied by
5
1
​
.
5
1
​
(15v − 10) = 8v + 8
= 8v + 8

Answer 1

To apply the distributive property and rewrite the expression \( 5(15v - 10) \):

1. Distribute the \( 5 \) to both terms inside the parentheses:

\[ 5(15v) - 5(10) \]

2. Calculate each term:

\[ 75v - 50 \]

Now the equation \( 5(15v - 10) = 8v + 8 \) becomes:

\[ 75v - 50 = 8v + 8 \]

Next, to isolate \( v \):

1. Get all the \( v \) terms on one side. Subtract \( 8v \) from both sides:

\[ 75v - 8v - 50 = 8 \]

This simplifies to:

\[ 67v - 50 = 8 \]

2. Next, add \( 50 \) to both sides to isolate the term with \( v \):

\[ 67v = 8 + 50 \]

Which simplifies to:

\[ 67v = 58 \]

3. Finally, divide both sides by \( 67 \) to solve for \( v \):

\[ v = \frac{58}{67} \]

So the solution for \( v \) is:

\[ v = \frac{58}{67} \]