Find the product. Simplify your answer.

Question

(j+3)(j–3)

Answer 1

To find the product \((j + 3)(j - 3)\), we can use the difference of squares formula, which states that \((a + b)(a - b) = a^2 - b^2\).

In this case, we can let \(a = j\) and \(b = 3\). Applying the formula:

\[ (j + 3)(j - 3) = j^2 - 3^2 \]

Calculating \(3^2\):

\[ 3^2 = 9 \]

Thus, we have:

\[ (j + 3)(j - 3) = j^2 - 9 \]

So, the simplified answer is:

\[ \boxed{j^2 - 9} \]

Answer 2

Yes, but some books use i = sqrt(-1) and some use j = sqrt(-1)
If the latter then j^2 = -1
and we have
-1 - 9 = -10