Question
Question 1
An SAT tutoring services charges an initial fee of $500 plus $50 for each additional session. David does not want to spend more than $700 on tutoring.
Which inequality should be used to determine the number of additional sessions (s) David can schedule?
(1 point)
Responses
50s +500>700
50s +500>700
50s + 500<700
50s + 500<700
50s + 500 ≤700
50s + 500 ≤700
50s + 500 ≥700
50s + 500 ≥700
Question 2
(1 point)
David can schedule
additional sessions.
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An SAT tutoring services charges an initial fee of $500 plus $50 for each additional session. David does not want to spend more than $700 on tutoring.
Which inequality should be used to determine the number of additional sessions (s) David can schedule?
(1 point)
Responses
50s +500>700
50s +500>700
50s + 500<700
50s + 500<700
50s + 500 ≤700
50s + 500 ≤700
50s + 500 ≥700
50s + 500 ≥700
Question 2
(1 point)
David can schedule
additional sessions.
Skip to navigation
Answers
GPT-4o mini
For Question 1, we need to set up an inequality that reflects David's spending limit of $700. The total cost includes an initial fee of $500 plus $50 for each additional session (denoted as \( s \)). So the expression for the total cost is:
\[ 500 + 50s \]
Since David does not want to spend more than $700, we set up the inequality:
\[ 500 + 50s \leq 700 \]
Thus, the correct response for Question 1 is:
**50s + 500 ≤ 700**
For Question 2, to find out how many additional sessions David can schedule, we solve the inequality:
\[ 500 + 50s \leq 700 \]
Subtract 500 from both sides:
\[ 50s \leq 200 \]
Now, divide each side by 50:
\[ s \leq 4 \]
This means David can schedule a maximum of **4 additional sessions**.
\[ 500 + 50s \]
Since David does not want to spend more than $700, we set up the inequality:
\[ 500 + 50s \leq 700 \]
Thus, the correct response for Question 1 is:
**50s + 500 ≤ 700**
For Question 2, to find out how many additional sessions David can schedule, we solve the inequality:
\[ 500 + 50s \leq 700 \]
Subtract 500 from both sides:
\[ 50s \leq 200 \]
Now, divide each side by 50:
\[ s \leq 4 \]
This means David can schedule a maximum of **4 additional sessions**.