Asked by Latoya
assume that a set of test score is normally distrubuted with a meanof 100 and a standard deviation of 20 find the quantities using the 68-95-99.7 rule to get:
the percentage of scores less than 100:
B) relative frequency of scores less than 120 c) percentage ofless than 140, D)percentage of less than 80, relative frequency of score less than 60,F) pertenage of scores greater than 120?
the percentage of scores less than 100:
B) relative frequency of scores less than 120 c) percentage ofless than 140, D)percentage of less than 80, relative frequency of score less than 60,F) pertenage of scores greater than 120?
Answers
Answered by
PsyDAG
A. In normal distribution, mean = median
Z = (score - mean)/SD
B. Z = +1, p = mean + 1/2 (68)
Use similar process for the remainder of the questions.
Z = (score - mean)/SD
B. Z = +1, p = mean + 1/2 (68)
Use similar process for the remainder of the questions.
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