calculate the delta h for the reaction 2C+2H--> C2H4

C+O2--> Co2 delta h= -393.5
C2H4+ 3O2--> 2CO2+ 2H2O delta h= 1410.9
H2+ 1/2 O2--> H2O delta h= -285.8
2CO+ O2--> 2CO2 delta h= -566.0

do you flip the first two equations and times the first and third one by 2?

Similar Questions
  1. Please explain.The enthalpy changes for two different hydrogenation reactions of C2H2 are: C2H2+H2---->C2H4 Delta H 1
    1. answers icon 0 answers
  2. Please explain.The enthalpy changes for two different hydrogenation reactions of C2H2 are: C2H2+H2---->C2H4 Delta H 1
    1. answers icon 1 answer
    1. answers icon 3 answers
  3. Calculate the enthalpy change for:C2H4(g) + H2 --> C2H6(g) delta Hrxn: H2(g) + 1/2O2 --> H2O (l) C2H4(g) + 3O2 --> 2H20(l) +
    1. answers icon 2 answers
more similar questions