Asked by jose

Okay I got this question on a test. I am not sure what I am supposed to do here. Can you show me how I would go about solving this.

A basketball player can jump 33in vertically. Find his hang time. Round to the nearest tenth.

Thanks
Answered by MathMate
The time to drop in free-fall for 33 inches (2.75') can be calculated by solving for:
S=ut+(1/2)gt²
2.75=0*t + (1/2)(32.2)t²
t=√(2*2.75/32.2)
=0.41 sec.
Thus time he is off-ground =2*0.41 sec=0.82 sec.
Answered by jose
What's that formula called?
Answered by GaRy
where did you get that 32.2 from?
There are no AI answers yet. The ability to request AI answers is coming soon!