Question
Which number is rational? (1 point)
Responses
15−−√
square root of 15
0.98989898...
0.98989898...
0.23242526...
0.23242526...
2√/4
Which number is rational? (1 point)
Responses
15−−√
square root of 15
0.98989898...
0.98989898...
0.23242526...
0.23242526...
2√/4
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To determine which number is rational, we first need to remember that a rational number is any number that can be expressed as the quotient of two integers (where the denominator is not zero) or as a terminating or repeating decimal.
Let's analyze each option:
1. **15−−√** (square root of 15): This number is irrational because the square root of a non-perfect square is not a fraction.
2. **0.98989898…:** This is a repeating decimal (0.98 repeated), which can be expressed as a fraction (specifically, \(\frac{98}{99}\)). Thus, it is a rational number.
3. **0.23242526…:** This number does not exhibit a repeating pattern and appears to be a non-repeating decimal, making it irrational.
4. **2√/4:** This can be simplified to \(\frac{2\sqrt{2}}{4} = \frac{\sqrt{2}}{2}\). The square root of 2 is irrational, so this is also irrational.
Based on this analysis, the rational number from the options given is:
**0.98989898…**
Let's analyze each option:
1. **15−−√** (square root of 15): This number is irrational because the square root of a non-perfect square is not a fraction.
2. **0.98989898…:** This is a repeating decimal (0.98 repeated), which can be expressed as a fraction (specifically, \(\frac{98}{99}\)). Thus, it is a rational number.
3. **0.23242526…:** This number does not exhibit a repeating pattern and appears to be a non-repeating decimal, making it irrational.
4. **2√/4:** This can be simplified to \(\frac{2\sqrt{2}}{4} = \frac{\sqrt{2}}{2}\). The square root of 2 is irrational, so this is also irrational.
Based on this analysis, the rational number from the options given is:
**0.98989898…**
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.