Question

Find the numerical equivalent of 2^5 ⋅2^−2
(1 point)
Responses

16
16

2
2

128
128

8

Answer 1

To solve \( 2^5 \cdot 2^{-2} \), you can use the property of exponents that states \( a^m \cdot a^n = a^{m+n} \).

Using this property:

\[
2^5 \cdot 2^{-2} = 2^{5 + (-2)} = 2^{5 - 2} = 2^3
\]

Now calculate \( 2^3 \):

\[
2^3 = 2 \cdot 2 \cdot 2 = 8
\]

So, the numerical equivalent of \( 2^5 \cdot 2^{-2} \) is \( 8 \).

The correct response is:

**8**