To find the final position of the object using the equation of motion \( x = x_0 + v_0 t + \frac{1}{2} a t^2 \), we can substitute the given values:
- Starting position \( x_0 = 2 , \text{m} \)
- Starting velocity \( v_0 = 4.5 , \text{m/s} \)
- Acceleration \( a = 0 , \text{m/s}^2 \) (since there is no acceleration)
- Time \( t = 2 , \text{s} \)
Substituting these values into the equation:
\[ x = 2 , \text{m} + (4.5 , \text{m/s})(2 , \text{s}) + \frac{1}{2}(0)(2^2) \]
Calculating each part:
\[ x = 2 , \text{m} + 9 , \text{m} + 0 \]
\[ x = 2 , \text{m} + 9 , \text{m} = 11 , \text{m} \]
The final position of the object after 2 seconds is 11 m.