Asked by Yes.
Using the included equations, compare the intercepts and intersection points of the square root and cube root functions.
f(x)=2√x and g(x)=2^3√x
Responses
They have no similar points
Both graphs share their x-and y-intercepts at (0, 0) and they also intersect at the point (1,2)
Both graphs intersect at the points (1, 2) and (0, 0), but they don't share any intercepts.
f(x)=2√x and g(x)=2^3√x
Responses
They have no similar points
Both graphs share their x-and y-intercepts at (0, 0) and they also intersect at the point (1,2)
Both graphs intersect at the points (1, 2) and (0, 0), but they don't share any intercepts.
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To compare the intercepts and intersection points of the functions \( f(x) = 2\sqrt{x} \) and \( g(x) = 2\sqrt[3]{x} \), we can analyze each function.
1. **Find the intercepts:**
- **For \( f(x) = 2\sqrt{x} \)**:
- **x-intercept**: Set \( f(x) = 0 \):
\[
2\sqrt{x} = 0 \implies \sqrt{x} = 0 \implies x = 0.
\]
Thus, the x-intercept is \( (0, 0) \).
- **y-intercept**: \( f(0) = 2\sqrt{0} = 0 \).
Thus, the y-intercept is also \( (0, 0) \).
- **For \( g(x) = 2\sqrt[3]{x} \)**:
- **x-intercept**: Set \( g(x) = 0 \):
\[
2\sqrt[3]{x} = 0 \implies \sqrt[3]{x} = 0 \implies x = 0.
\]
Thus, the x-intercept is \( (0, 0) \).
- **y-intercept**: \( g(0) = 2\sqrt[3]{0} = 0 \).
Thus, the y-intercept is also \( (0, 0) \).
2. **Find intersection points:**
We need to set \( f(x) \) equal to \( g(x) \):
\[
2\sqrt{x} = 2\sqrt[3]{x}.
\]
Dividing both sides by 2 (as long as \( x \geq 0 \)), we get:
\[
\sqrt{x} = \sqrt[3]{x}.
\]
Raising both sides to the power of 6 (to eliminate the roots):
\[
x^3 = x^2.
\]
Rearranging gives:
\[
x^3 - x^2 = 0 \implies x^2(x - 1) = 0.
\]
Thus, \( x = 0 \) or \( x = 1 \).
- **At \( x = 0 \)**: \( f(0) = g(0) = 0 \), so the point is \( (0, 0) \).
- **At \( x = 1 \)**: \( f(1) = 2\sqrt{1} = 2 \) and \( g(1) = 2\sqrt[3]{1} = 2 \), so the point is \( (1, 2) \).
3. **Conclusion**:
Both functions share their x- and y-intercepts at \( (0, 0) \) and they also intersect at the point \( (1, 2) \).
Thus, the correct response is:
**Both graphs share their x-and y-intercepts at (0, 0) and they also intersect at the point (1, 2).**
1. **Find the intercepts:**
- **For \( f(x) = 2\sqrt{x} \)**:
- **x-intercept**: Set \( f(x) = 0 \):
\[
2\sqrt{x} = 0 \implies \sqrt{x} = 0 \implies x = 0.
\]
Thus, the x-intercept is \( (0, 0) \).
- **y-intercept**: \( f(0) = 2\sqrt{0} = 0 \).
Thus, the y-intercept is also \( (0, 0) \).
- **For \( g(x) = 2\sqrt[3]{x} \)**:
- **x-intercept**: Set \( g(x) = 0 \):
\[
2\sqrt[3]{x} = 0 \implies \sqrt[3]{x} = 0 \implies x = 0.
\]
Thus, the x-intercept is \( (0, 0) \).
- **y-intercept**: \( g(0) = 2\sqrt[3]{0} = 0 \).
Thus, the y-intercept is also \( (0, 0) \).
2. **Find intersection points:**
We need to set \( f(x) \) equal to \( g(x) \):
\[
2\sqrt{x} = 2\sqrt[3]{x}.
\]
Dividing both sides by 2 (as long as \( x \geq 0 \)), we get:
\[
\sqrt{x} = \sqrt[3]{x}.
\]
Raising both sides to the power of 6 (to eliminate the roots):
\[
x^3 = x^2.
\]
Rearranging gives:
\[
x^3 - x^2 = 0 \implies x^2(x - 1) = 0.
\]
Thus, \( x = 0 \) or \( x = 1 \).
- **At \( x = 0 \)**: \( f(0) = g(0) = 0 \), so the point is \( (0, 0) \).
- **At \( x = 1 \)**: \( f(1) = 2\sqrt{1} = 2 \) and \( g(1) = 2\sqrt[3]{1} = 2 \), so the point is \( (1, 2) \).
3. **Conclusion**:
Both functions share their x- and y-intercepts at \( (0, 0) \) and they also intersect at the point \( (1, 2) \).
Thus, the correct response is:
**Both graphs share their x-and y-intercepts at (0, 0) and they also intersect at the point (1, 2).**
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