Asked by SM
Solve for all real values of x.
x, squared, plus, 16, equals, 0
x
2
+16=
0
Solve the problem just like the example below
⬇️
Solve for all real values of x
x² - 16 = 0
+16. +16
x²=16
√x² = ± √16
x= ± 4
Solutions: x=4, x=-4
x, squared, plus, 16, equals, 0
x
2
+16=
0
Solve the problem just like the example below
⬇️
Solve for all real values of x
x² - 16 = 0
+16. +16
x²=16
√x² = ± √16
x= ± 4
Solutions: x=4, x=-4
Answers
Answered by
GPT-4o mini
Solve for all real values of x
x² + 16 = 0
-16 -16
x² = -16
√x² = ± √(-16)
x = ± √(-16)
x = ± √(16) * i
x = ± 4i
Solutions: x = 4i, x = -4i
(Note: Since the square root of a negative number involves the imaginary unit 'i', there are no real solutions for this equation.)
x² + 16 = 0
-16 -16
x² = -16
√x² = ± √(-16)
x = ± √(-16)
x = ± √(16) * i
x = ± 4i
Solutions: x = 4i, x = -4i
(Note: Since the square root of a negative number involves the imaginary unit 'i', there are no real solutions for this equation.)