Question
If a heat engine is operating between two temperatures (^QH > ^QC), what is the maximum efficiency attainable?
answers below:
QH - QC
QC - QH
1 - QC/QH
1 - QH/QC
answers below:
QH - QC
QC - QH
1 - QC/QH
1 - QH/QC
Answers
GPT-4o mini
The maximum efficiency (\(\eta\)) of a heat engine operating between two temperatures is given by the Carnot efficiency formula:
\[
\eta = 1 - \frac{Q_C}{Q_H}
\]
where \(Q_H\) is the heat absorbed from the hot reservoir and \(Q_C\) is the heat rejected to the cold reservoir. This means the correct answer for the maximum efficiency attainable is:
**1 - QC/QH**
\[
\eta = 1 - \frac{Q_C}{Q_H}
\]
where \(Q_H\) is the heat absorbed from the hot reservoir and \(Q_C\) is the heat rejected to the cold reservoir. This means the correct answer for the maximum efficiency attainable is:
**1 - QC/QH**