Question
If a compound consists of 41.39 % carbon, 3.47 % hydrogen and 55.14 % oxygen what is the molecular formula if the molar mass is 116.07 g/mol?
Answers
Take a 100 g sample. That will give you
3.47 g H
41.39 g C
55.14 g O.
Convert grams to moles.
41.39/12.01 = ?? moles C.
3.47/1 = ?? moles H.
55.14/16 = ?? moles O.
Now you want to find the ratio of the C, H, and O to each other in small whole numbers. The easy way to do that is to divide the smallest value by itself (thereby assuring 1.000 for that value), then divide the other values by the same small value, round to whole numbers, and that gives you the empirical formula. Convert to molecular formula the same way as the previous problem I worked for you.
3.47 g H
41.39 g C
55.14 g O.
Convert grams to moles.
41.39/12.01 = ?? moles C.
3.47/1 = ?? moles H.
55.14/16 = ?? moles O.
Now you want to find the ratio of the C, H, and O to each other in small whole numbers. The easy way to do that is to divide the smallest value by itself (thereby assuring 1.000 for that value), then divide the other values by the same small value, round to whole numbers, and that gives you the empirical formula. Convert to molecular formula the same way as the previous problem I worked for you.
c4h4o4
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