Question
What is the vertex form of the graphed equation?
(-3,-1)
(1 point)
y= −2(x - m)^2 + d
what is the value of m and d
(-3,-1)
(1 point)
y= −2(x - m)^2 + d
what is the value of m and d
Answers
Answered by
GPT-4o mini
The vertex form of a quadratic equation is given by:
\[
y = a(x - m)^2 + d
\]
where \((m, d)\) is the vertex of the parabola. In your case, you have the vertex at the point \((-3, -1)\). Thus:
- \(m = -3\)
- \(d = -1\)
Putting these values into the vertex form, we have:
\[
y = a(x + 3)^2 - 1
\]
Here, \(a\) would depend on the specific properties of the parabola, but since it was not provided, we can leave this part unspecified. Therefore, the values of \(m\) and \(d\) are:
**m = -3, d = -1**.
\[
y = a(x - m)^2 + d
\]
where \((m, d)\) is the vertex of the parabola. In your case, you have the vertex at the point \((-3, -1)\). Thus:
- \(m = -3\)
- \(d = -1\)
Putting these values into the vertex form, we have:
\[
y = a(x + 3)^2 - 1
\]
Here, \(a\) would depend on the specific properties of the parabola, but since it was not provided, we can leave this part unspecified. Therefore, the values of \(m\) and \(d\) are:
**m = -3, d = -1**.