To compare the averages and deviations of the two graphs:
- Graph 1 has a mean (center) of 7 and a deviation (average distance from the mean) of 5.
- Graph 2 has a mean (center) of 10 and a deviation of 5.
Comparing Centers: The mean of Graph 1 is 7, and the mean of Graph 2 is 10. The difference between the two centers is: 10 - 7 = 3
So, the center of Graph 1 is 3 units away from the center of Graph 2.
Comparing Average Deviations: Both graphs have the same deviation of 5. This means that on average, the points in both graphs are 5 units away from their respective centers.
Now, looking at the options provided:
- "The two graphs have the same center and points are on average three away from the center." - Incorrect (centers are not the same).
- "The center of graph 1 is seven places away from graph 2 and points are on average five away from the center in both graphs." - Incorrect (the centers are 3 places away, not 7).
- "The center of graph 1 is three places away from graph 2 and points are on average five away from the center in both graphs." - Correct! (the distance is accurately stated, and deviations are equal).
- "The center of graph 1 is five places away from graph 2 and points are on average 8.5 away from the center." - Incorrect (the center is incorrectly stated, and the average deviation is not 8.5).
Thus, the correct response is:
"The center of graph 1 is three places away from graph 2 and points are on average five away from the center in both graphs."
1 answer