To calculate the atomic mass of Fe(OH)₃, we need to consider the components of the compound:
- Iron (Fe): 1 atom × 56 amu = 56 amu
- Oxygen (O): 3 atoms × 16 amu = 48 amu (since there are 3 hydroxide groups, each containing one oxygen)
- Hydrogen (H): 3 atoms × 1 amu = 3 amu (since there are 3 hydroxide groups, each containing one hydrogen)
Now, we can sum these contributions to get the total atomic mass of Fe(OH)₃:
\[ \text{Total atomic mass} = \text{mass of Fe} + \text{mass of O} + \text{mass of H} \] \[ \text{Total atomic mass} = 56 , \text{amu} + 48 , \text{amu} + 3 , \text{amu} = 107 , \text{amu} \]
Thus, the atomic mass of Fe(OH)₃ is 107 amu.