To find the volume of a cone, you can use the formula:
\[ V = \frac{1}{3} \pi r^2 h \]
where:
- \( V \) is the volume,
- \( r \) is the radius of the base,
- \( h \) is the height of the cone.
In your case, you mentioned that the cone is 14 inches and 11 inches. Assuming that:
- 14 inches is the height (\( h \))
- 11 inches is the diameter of the base, which means the radius (\( r \)) is half of that:
\[ r = \frac{11}{2} = 5.5 \text{ inches} \] \[ h = 14 \text{ inches} \]
Now plug these values into the volume formula:
\[ V = \frac{1}{3} \pi (5.5)^2 (14) \]
Calculating \( (5.5)^2 \):
\[ (5.5)^2 = 30.25 \]
Now substituting back into the volume equation:
\[ V = \frac{1}{3} \pi (30.25)(14) \] \[ V = \frac{1}{3} \pi (423.5) \] \[ V \approx \frac{423.5}{3} \pi \] \[ V \approx 141.1667 \pi \]
Using \( \pi \approx 3.14159 \):
\[ V \approx 141.1667 \times 3.14159 \approx 443.62 \text{ cubic inches} \]
Therefore, the volume of the cone is approximately 443.62 cubic inches.
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