Asked by coco
Data collected from the calorimetry of a metal
mass of the metal = 110.62g
initial temperature of the water in the cup = 23.0 C
initial temperature of the metal in the boiling water = 99.02 C
final temperature of the metal AND water in the cup=25.54C
volume of the water =100.0ml
1. What is the mass of the water?
2. What is the change in temperature of the water?
3. What is the change in temperature of the metal?
4. What is the specific heat of the metal?
mass of the metal = 110.62g
initial temperature of the water in the cup = 23.0 C
initial temperature of the metal in the boiling water = 99.02 C
final temperature of the metal AND water in the cup=25.54C
volume of the water =100.0ml
1. What is the mass of the water?
2. What is the change in temperature of the water?
3. What is the change in temperature of the metal?
4. What is the specific heat of the metal?
Answers
Answered by
DrBob222
I assume the density of the water is 1.00 g/mL but there is nothing in the problem to support that.
[mass metal x specific heat metal x (Tfinal-Tinitial)] + [mass water x specific heat water x (Tfinal-Tinital)] = 0
I believe the only unknown is specific heat metal.
[mass metal x specific heat metal x (Tfinal-Tinitial)] + [mass water x specific heat water x (Tfinal-Tinital)] = 0
I believe the only unknown is specific heat metal.
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