A shipping container will be used to transport several 70-kilogram crates across the country by rail. The greatest weight that can be loaded into the container is 23500 kilograms. Other shipments weighing 13000 kilograms have already been loaded into the container. Which inequality can be used to determine xx, the greatest number of 70-kilogram crates that can be loaded onto the shipping container?

Answer
Multiple Choice Answers
70, left parenthesis, x, plus, 13000, right parenthesis, is less than or equal to, 2350070(x+13000)≤23500
23500, is greater than or equal to, 70, x, plus, 1300023500≥70x+13000
23500, is less than or equal to, 70, x, plus, 1300023500≤70x+13000
70, left parenthesis, x, plus, 13000, right parenthesis, is greater than or equal to, 2350070(x+13000)≥23500

1 answer

To determine the greatest number of 70-kilogram crates that can be loaded onto the shipping container, we need to represent the situation with an inequality.

You start with the maximum weight capacity of the container, which is 23,500 kilograms. From this weight, we need to subtract the weight of the already-loaded shipments (13,000 kilograms). The remaining weight capacity is the difference between the maximum capacity and the weight of the already-loaded shipments:

Remaining weight capacity: \( 23500 - 13000 = 10500 \) kilograms

Since each crate weighs 70 kilograms, the total weight of \( x \) crates is \( 70x \). Therefore, the inequality that represents this situation becomes:

\[ 70x \leq 10500 \]

Now, if we rewrite this to reflect the situation presented in the question, we can express it as follows:

\[ 70(x) + 13000 \leq 23500 \]

This means that the weight of the crates plus the weight of the already-loaded shipments cannot exceed the container's maximum weight capacity.

Among the options provided, the correct inequality is:

70(x) + 13000 ≤ 23500

So the answer is:

70, left parenthesis, x, plus, 13000, right parenthesis, is less than or equal to, 23500 (70(x) + 13000 ≤ 23500).